The angular frequency of a simple pendulum is Ω rad/s. Now the length is made one fourth of the original length, the angular frequency becomes
The angular frequency of a simple pendulum is Ω rad/s. Now the length is made one fourth of the original length, the angular frequency becomes
Option 1 -
Ω/2
Option 2 -
2Ω
Option 3 -
4Ω
Option 4 -
Ω
-
1 Answer
-
Correct Option - 2
Detailed Solution:
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According to question, we can write
Kindly consider the following Image
(1/2)mu² = (1/2)mv² + mgl (1-cosθ)
⇒ v² = u² - 2gl (1-cosθ)
⇒ v² = 3² - 2×10×0.5× (1 - 1/2)
⇒ v² = 9 - 5 = 4
v = 2m/s

Total oscillation =
= 7
Time period of second pendulum is 2 seconds. &nbs
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