The motion of a simple pendulum executing S.H.M. is represented by the following equation.
where time is measured in second.
The length of pendulum is
The motion of a simple pendulum executing S.H.M. is represented by the following equation. where time is measured in second.
The length of pendulum is
Option 1 -
97.23 cm
Option 2 -
25.3 cm
Option 3 -
99.4 cm
Option 4 -
406.1 cm
-
1 Answer
-
Correct Option - 3
Detailed Solution:According to question, we can write
Similar Questions for you
Kindly consider the following Image
(1/2)mu² = (1/2)mv² + mgl (1-cosθ)
⇒ v² = u² - 2gl (1-cosθ)
⇒ v² = 3² - 2×10×0.5× (1 - 1/2)
⇒ v² = 9 - 5 = 4
v = 2m/s

Total oscillation =
= 7
Time period of second pendulum is 2 seconds. &nbs
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