The motion of a simple pendulum executing S.H.M. is represented by the following equation. $y = A s i n (π t + ϕ),$ where time is measured in second.

The length of pendulum is

alok kumar singh

According to question, we can write

$ω = π = \sqrt[]{\frac{g}{l}} \Rightarrow l = \frac{g}{π^{2}} = \frac{9.8}{{(3.14)}^{2}} = 0.99395 = 99.4 c m$

Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g / 2, the time period of pendulum will be:

Raj Pandey

Kindly consider the following Image

A pendulum bob has a speed of 3 m/s at its lowest position. The pendulum is 50 cm long. The speed of the bob, when the length makes an angle of 60° to the vertical will be _______ m/s. (g = 10 m/s²)

Raj Pandey

(1/2)mu² = (1/2)mv² + mgl (1-cosθ)
⇒ v² = u² - 2gl (1-cosθ)
⇒ v² = 3² - 2×10×0.5× (1 - 1/2)
⇒ v² = 9 - 5 = 4
v = 2m/s

Given below are two statements:

Statement I : A second’s pendulum has a time period of 1 second.

Statement II : It takes precisely one second to move between the two extreme positions.

In the light of the above statements, choose the correct answer from the options given below:

Vishal Baghel

Time period of second pendulum is 2 seconds. &nbs

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Time period of a simple pendulum is T. The time taken to complete 5 8 oscillations starting from mean position is α β T . The value of a is………..