Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g / 2, the time period of pendulum will be:
Time period of a simple pendulum is T inside a lift when the lift is stationary. If the lift moves upwards with an acceleration g / 2, the time period of pendulum will be:
Option 1 -
√2/3 T
Option 2 -
√3T
Option 3 -
T/√3
Option 4 -
√3/2 T
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1 Answer
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Correct Option - 3
Detailed Solution:Kindly consider the following Image
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According to question, we can write
(1/2)mu² = (1/2)mv² + mgl (1-cosθ)
⇒ v² = u² - 2gl (1-cosθ)
⇒ v² = 3² - 2×10×0.5× (1 - 1/2)
⇒ v² = 9 - 5 = 4
v = 2m/s

Total oscillation =
= 7
Time period of second pendulum is 2 seconds. &nbs
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