The intensity of a light pulse travelling along a communication channel decreases exponentially with distance x according to the relation I = I0e-ax, where I0is the intensity at x = 0 and α is the attenuation constant.
(a) Show that the intensity reduces by 75% after a distance of  (In4/α).
(b) Attenuation of a signal can be expressed in decibel (dB) according to the relation dB=10 log10(I/I0).What is the attenuation in dB/km for an optical fibre in which the intensity falls by 50% over a distance of 50 km?

0 3 Views | Posted 4 months ago
Asked by Shiksha User

  • 2 Answers

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    This is a Long Answer Type Questions as classified in NCERT Exemplar

    as we know that I= I0 e - x

    And I= 25%of I0=

    I=I0/4

    I0/4= I0 e - x

    I0 cancel from both sides

    ¼= e - x

    Taking log on both sides log1 -log4= - x loge

    X= log4/

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    This is a Long Answer Type Questions as classified in NCERT Exemplar

    as we know that I= I0 e - ? x

    And I= 25%of I0=

    I=I0/4

    I0/4= I0 e - ? x

    I0 cancel from both sides

    ¼= e - ? x

    Taking log on both sides log1 -log4= - ? x loge

    X= log4/ ?

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