The intensity of a light pulse travelling along a communication channel decreases exponentially with distance x according to the relation I = I0e-ax, where I0is the intensity at x = 0 and α is the attenuation constant.
(a) Show that the intensity reduces by 75% after a distance of (In4/α).
(b) Attenuation of a signal can be expressed in decibel (dB) according to the relation dB=10 log10(I/I0).What is the attenuation in dB/km for an optical fibre in which the intensity falls by 50% over a distance of 50 km?
The intensity of a light pulse travelling along a communication channel decreases exponentially with distance x according to the relation I = I0e-ax, where I0is the intensity at x = 0 and α is the attenuation constant.
(a) Show that the intensity reduces by 75% after a distance of (In4/α).
(b) Attenuation of a signal can be expressed in decibel (dB) according to the relation dB=10 log10(I/I0).What is the attenuation in dB/km for an optical fibre in which the intensity falls by 50% over a distance of 50 km?
This is a Long Answer Type Questions as classified in NCERT Exemplar
as we know that I= I0
And I= 25%of I0=
I=I0/4
I0/4= I0
I0 cancel from both sides
¼=
Taking log on both sides log1 -log4= - loge
X= log4/
This is a Long Answer Type Questions as classified in NCERT Exemplar
as we know that I= I0
And I= 25%of I0=
I=I0/4
I0/4= I0
I0 cancel from both sides
¼=
Taking log on both sides log1 -log4= - loge
X= log4/
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Physics NCERT Exemplar Solutions Class 12th Chapter Fifteen 2025
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