The vector sum of a system of non-collinear forces acting on a rigid body is given to be non-zero. If the vector sum of all the torques due to the system of forces about a certain point is found to be zero, does this mean that it is necessarily zero about any arbitrary point?
The vector sum of a system of non-collinear forces acting on a rigid body is given to be non-zero. If the vector sum of all the torques due to the system of forces about a certain point is found to be zero, does this mean that it is necessarily zero about any arbitrary point?
This is a short answer type question as classified in NCERT Exemplar
no
The sum of torques about a certain point O
The sum of torques about any other O
The sum of torques about any other point O'
Here the second term need not vanish.
Sum of all torques about any point is zero.
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a, b, d
a) according to the perpendicular axes theorem statement 1 is wrong
b) As z’|z so distance between them = a
So according to parallel axes theorem Iz’=Iz+m (a/ )2= Iz+ma2/2
Hence b is true
c) z’ is not parallel to z hence Pa
This is a multiple choice type question as classified in NCERT Exemplar
b, c
a) When r>r’

Torque about z-axis t=r F
b) t’=r’ which is along negative z axis
c) tz=Fr = magnitude of torque about z axis where r is perpendicular between F and z axis so torque along positive z axis is greater than negative
This is a multiple choice type question as classified in NCERT Exemplar
a, b, c, d
As we know torque = r F = rFsin
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b) when forces are acting on the axis of rotation r=0 torque=0
c) when forces acting parallel to the axis of rotation angle =0 so torq
This is a multiple choice type question as classified in NCERT Exemplar
(a), (b)As we know L= r p where r is position vector and p is the linear momentum . the direction of L is perpendicular to both r and p by right hand rule.
For particle 1
I1=r1 mv is out of the plane of the paper and perpendicu
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Physics NCERT Exemplar Solutions Class 11th Chapter Seven 2025
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