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Example problems for you, lynch :
Q9) The form of Coulomb's law is very similar to that for Newton's law of universal gravitation.
What are the differences between these two laws? Compare also gravitational mass and electric charge.
SOLUTION:The gravitational force is always attractive, and the magnitude of the force is: Gm1m2/r2. The electric force is attractive if the charges have opposite signs, and is repulsive if the charges have the same sign. The force magnitude is: kq1q2/r2. The gravitational and electric force are very similar in each having the inverse distance- squared rule, and in having the magnitudes depending in a linear and symmetric fashion on properties of the two objects. The major difference is that possibility of repulsion for the electric force.
P2)Two charged smoke particles exert a force of 4.2 x 10-2 N on each other. What will be the force if they are moved so they are only one eighth as far apart?
SOLUTION:F=kq1q2/r2 = 4.2 x10-2 N If r -> (1/8)r, r2 -> (1/64)r2 and so,F = 64(4.2 x 10-2 N) = 1.69 N
P6)What is the repulsive electrical force between two protons in a nucleus that are 5.0 x10-15 m apart?
SOLUTION:F = (9 x 109 Nm2/C2)(1.6 x 10-19 C)2 / (5.0 x10-15 m)2 = 9.2 N
P8)A person scuffing her feet on a wool rug on a dry day accumulates a net charge of -60 µC.
How many excess electrons does this person get, and by how much does her mass increase?
SOLUTION:Q = -60 µC, so the number of electrons is the total charge divided by the charge per electron:Ne = Q / (-e) = 60 µC/1.6x10-19 C= 60 x10-6/1.6x10-19 = 3.75 x 1014 excess electrons.
The additional mass due to the excess electrons is the number of electrons multiplied by
the mass per electron:Ne( 9.11 x 10-31kg) = 3.42 x10-16 kg
P11)Particles of charge +70, +48, and -80 µC are placed in a line. The center one is 0.35m from
each of the others. Calculate the net force on each due to the other two (see Fig. 16-37 in text book).
SOLUTION:Let Q1 = 70 µC , Q2 = 48 µC, Q3 = -80 µCLet the x axis lie along the charges. We will calculate the x component of the forces (the other components vanish).F1x = F12x + F13x = -k | Q1Q2 | / (0.35 m)2 + k | Q1Q3 | / (0.70 m)2F1x = [(9.0 x 109 Nm2/C2) / (0.70 m)2] x (70 µC) [-4 (48µC) + 80 µC]= -144 N (force is to the left, indicated by negative value)F2x = F21x + F23x = k | Q1Q2 | / (0.35 m)2 + k | Q2Q3 | / (0.35 m)2F2x = [(9.0 x 109 Nm2/C2) / (0.35 m)2]

The strength of electric field at a particular point is called as Electric Field intensity. In other words, the force felt by a unit positive charge situated at a point is called Electric field intensity.
Electric field intensity is a vector quantity means it has magnitude as well as direction. The direction of electrostatic 1.39 is similar to that of electrostatic 1.38 means electrostatic 1.39 is in the similar direction in which the test charge q 0 tends to go.
Newton per coulomb is the S.I. unit of Electric field intensity. Electric field electrostatic 1.39 is generated by a source charge placed anywhere. The charge present at source can be a combination of a no. of different charges or it may be a single charge or any continuous distribution of charge. The test charge +q 0 can have its self electric field, which have the ability to modify the electric field of the charge present at source. So, to reduce or remove its effect, we will write the equation of electric field intensity in some different way.
As we know that the charge electrostatic 1.36 is inversely proportional to the electric field intensity electrostatics 2.1
So as we increase the charge electric field intensity decreases. Due to the charges having individual nature the minimum value of charge is 1.6 X 10 -19 coulomb. The value of charge can never be zero.
The major importance and use of electric field is that, it can be used to calculate the direction and magnitude of the force felt by a charge present at a particular point affected by electric field.
Note: The direction of electric field intensity is same as that of direction of force applied on a positive charge.

Hi Harsh,
Well as you are already pursuing MBA, you should concentrate on that and take up photography as a passion or hobby.
Photography is a very challenging profession and requires a lot of hard work time and patience. In order to learn this art, you can go for a short term diploma or a certificate course. There are various institutes that provide courses in photography
The Shari Academy of Professional Photography and Digital Imaging - Mumba
Delhi School of Photography - Delhi
For more institutes and details regarding Photography, refer to the below link
tinyurl.com/y8wn557
(Simply copy paste this url and select your preferred city to get the list of institutes)
However, The best way to learn the art of photography is becoming the apprentice of senior photographers.
Photographers usually are free lancers or are associated with Print Journalism. Also apart from Journalism you can go for Fashion photography, wildlife photography, industrial photography, forensic photography, portrait photography, freelance photography etc. All that you would need is a good hand on camera and the art of capturing and showing the reality behind picture.
Hope this helps.
Thanks
All The Best!

Hi,
Yes, you may surely take marketing as your major and total quality management as minor specialization in MBA, there are an enormous amount of career opportunities and options for people with MBA in marketing.
The most common are corporate positions such as marketing manager, brand manager, market research analyst, and new product manager.
Persons with strong financial skills could seek a career in strategic or market related planning.
Additional corporate positions such as sales manager, advertising manager, PR (public relations) director, and marketing communications manager are also common.
However, besides marketing you may also consider finance or operations management as your specialization in MBA.
For your reference, find below some of the finest universities to pursue MBA through distance education:
- Indira Gandhi National Open University.
- Punjab Technical University.
- Sikkim Manipal University.
- Symbiosis Centre for Distance Learning.
- University of Mumbai.
- Yashwantrao Chavan Maharashtra Open University.
- Karnataka State Open University.
Feel free to raise more questions. Appreciate by giving it thumbs up or marking as best.
All the Best.