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$r_1=k{\left[x\right]}^n$ … (i)

$$ $2r_1=k{\left[4x\right]}^n$  … (ii)

$\left(ii\right)÷\left(i\right)$

$\Rightarrow \frac{2r_1}{r_1}=\frac{k{\left[4x\right]}^n}{k{\left[x\right]}^n}$

$\Rightarrow 2={\left(2\right)}^{2n}$

$\Rightarrow n=\frac{1}{2}$

$A_1=\sqrt[]{{\left(5\right)}^2+{\left(5\sqrt[]{3}\right)}^2}=10$

$A_2=5$

Then, $\frac{A_1}{A_2}=\frac{10}{5}=\frac{2}{1}$

For a first order reaction.

$k=\frac{0.693}{t_{\raisebox{1ex}{$1$}\!\left/ \!\raisebox{-1ex}{$2$}\right.}}=\frac{0.693}{231}=3\times 10^{-3}{s}^{-1}$   

Z=109 : Unnilennium = Meitnerium

The VTUEEE exam centres are located across major cities in India and candidates can choose the exam centres as per their choice.

Sn = [Kr]4d105s25p2

Sn (Z = 50) belongs to p-block element.

$5C_2{O}_4^{2-}+2Mn{O}_4^{-}+16H^{+}\to 2M{n}^{+}+8H_{2}O+10C{O}_2$

5 moles of $C_2{O}_4^{2-}$ ${}_{}{}_{}^{}$ is needed to reduce 2 moles of $Mn{O}_4^{2-}$ ${}_{}^{}$

1 mole of $C_2{O}_4^{2-}$  is needed to reduce $\frac{2}{5}$  moles of $Mn{O}_4^{2-}$

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$\underset{acid}{H_{3}B{O}_3}+2H_{2}O\underset{conjugatebase}{B{\left(OH\right)}_4^{-}+}{H}_3{O}^{+}$

H2SO5

: x + 2 (+1) + 3 (–2) + 2 (–1) = 0

x = + 6.

On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.

CH₃COONa is salt of weak acid with strong base

$\therefore pH=7+\frac{1}{2}p{K}_a+\frac{1}{2}logC$

$pH=7+\frac{1}{2}\times 4.74+\frac{1}{2}\times log1$

$pH=9.37\approx 9.4$

  $\Delta G=\Delta H-T\Delta S$

For spontaneity

$\begin{array}{l}\Delta G=-ve\\ \Delta S=+ve\\ \Delta H=-ve\end{array}$        

·   $\Delta S$ is a state function because its value depends only on the state of the system and not on how it is reached.

· Entropy is an extensive property because its value depends on the quantity of matter present in the system.

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Yes, a material's resistivity will increase with the presence of impurities. This is because these impurities will occupy more surface area and disrupt the flow of electrons which will impact their free movement. As a result, the current cannot pass freely through the material and it will affect the resistivity.

Kindly go through the solution

K_h = Kw/Ka = 2.22 x 10^-5

Resistance is referred to the ability of an object to oppose the flow of electric current through itself. On the other hand, resistivity is the property of that particular material of resisting the passage of electric current over a particular unit area. Resistance has SI unit ohm whereas resistivity has ohm-metre.

Total kinetic energy associated with 'n' moles of monoatomic gas is =   $\frac{3}{2}nRT$

In physisorption multimolecular layers are formed on solid surface.