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2 years agoContributor-Level 8
NSUT (formerly NSIT) accepts only GATE scores for admission to M.Tech programmes. Candidates should have a valid GATE score and rank, as well as a B.Tech or AMIE degree in the relevant discipline with at least 55% marks. The admission is based on the GATE score and rank, followed by counselling through JAC Delhi.
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2 years agoContributor-Level 8
The minimum marks required for M.Tech at NSUT (formerly NSIT) in 2023 depend on the branch, category, and GATE score of the candidate. The admission is based on the GATE score and rank, followed by counselling through JAC Delhi. The cutoff marks vary every year depending on the difficulty level of the exam, number of seats available, number of candidates registered and appeared, etc.
The cutoff marks for M.Tech at NSUT for the year 2021 (Round 7) are as follows :
| Branch | General Category |
| Bioinformatics | 361 |
| Computer Science and Engineering | 367 |
| Electrical Engineering | 350 |
| Mobile Communication & Network Technology | 371 |
| VLSI Design & Embedded System | 376 |
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2 years agoContributor-Level 9
The eligibility requirements of 60% are merely the minimum. The 12th grade is not directly taken into account for admission by NSIT.To have a chance in the General category with 60% in the 12th grade, you would need a JEE Main rank below 500.NSIT and DTU ask for an aggregate of 60% or more in PCM and passing them along with English in 12th, so yes you're eligible for them. IIITD, on the other hand, demands 80%. These are for general category.To apply, a candidate should have cleared 10+2 with Physics, Mathematics and Chemistry/Biotechnology with 75% marks or should feature among the top 20 percentile. For selection, the candidate has t
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2 years agoContributor-Level 8
To get admission in B.Tech at NSUT (formerly NSIT), you need to have a good rank and score in JEE Main, as well as meet the eligibility criteria of the branch and category you are applying for. The cutoff marks vary every year depending on various factors.
According to the web search results, you can convert your JEE percentile to rank using the following formula? :
{JEE Main rank} = (100 - JEE percentile)* N/100 + 1
where N is the total number of candidates who appeared for JEE Main.
Using this formula, your JEE Main rank with 75 percentile would be approximately:
JEE Main rank = (100 - 75)*869010/100 + 1= 217253
This rank is mu
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2 years agoContributor-Level 8
To be eligible for the M.Tech programme at NSUT (formerly NSIT), candidates should have either a 4-year Bachelor's Degree in Engineering/Technology or a Master's degree in Science, Computer Applications, or its equivalent. The admission is based on the GATE score and rank, followed by counselling through JAC Delhi. The minimum GATE score required varies for different branches and categories of candidates. You can check the previous year cutoffs for different branches.
I hope this information helps you. If you have any other queries, feel free to ask me.
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2 years agoContributor-Level 10
A state-level institution, Netaji Subhas institution of Technology (NSUT) was earlier known as Netaji Subhas Institute of Technology (NSIT). NSIT was founded in 1983 and granted university status in 2018, which means that it is now a non-affiliating university. It was formerly connected to the University of Delhi. By NIRF 2021, NSUT is ranked 88th for BTech. The AICTE, UGC, and NAAC have all approved NSIT Delhi. Thirteen departments make up NSIT, and they provide eleven undergraduate, fifteen graduate, and eleven doctorate programmes in diverse fields like computer and electrical engineering. Among the leading businesses participating
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2 years agoContributor-Level 8
The cutoff marks for B.Tech at NSUT (formerly NSIT) depend on the branch, category, and region of the candidate. The admission is based on the JEE Main rank and score, followed by Joint Admission Counselling (JAC) Delhi. The cutoff marks vary every year depending on the difficulty level of the exam, number of seats available, number of candidates registered and appeared, etc.
According to the latest data available, the cutoff marks for B.Tech at NSUT for the year 2021 (Round 7) are as follows²:
| Branch | Delhi Region | Outside Delhi Region |
| Bio-Technology | 73223 | 18894 |
| Computer Science and Engineering | 7453 | 2536 |
| Computer Science and Engineering with specialisation in Artificial Intelligence | 4310 | 2117 |
| Computer Science and Engineering with specialisation in Data Science | 9703 | 3217 |
| Electrical Engineering | 37826 | 9106 |
| Electronics and Communication Engineering | 25985 | 6703 |
| Electronics and Communication Engineering with specialisation in Internet of Things | 21324 | 6122 |
| Information Technology | 12434 | 4094 |
| Information Technology with specialisation in Network and Information Security | 15212 | 5017 |
| Instrumentation and Control Engineering | 43806 | 12052 |
| Mathematics and Computing | 17928 | 5270 |
| Mechanical Engineering | 52040 | 13632 |
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2 years agoContributor-Level 8
The minimum cutoff for M.Tech at NSIT 2023 has not been announced yet, but you can refer to the previous year's cutoffs from various sources. The GATE cutoff for M.Tech Computer Science and Engineering in 2022 was 367 for general category candidates.The GATE cutoff for M.Tech Information Technology in 2022 was 350 for general category candidates. The cutoff may vary depending on the branch, category, and number of applicants. You can check the official website of [JAC Delhi] for the latest updates on the NSIT M.Tech admission process. I hope this helps.
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2 years agoContributor-Level 8
According to the NSIT eligibility criteria, you need to have at least 60% aggregate marks in Physics, Chemistry, and Mathematics in your qualifying exams / 12th from a recognised center or state board. You also need to pass English as a core or elective subject in 10+2, and pass in each subject separately. Additionally, you need to qualify for JEE Main and register for JAC Delhi counseling.
If you meet these requirements, you have a chance of getting into NSIT, depending on your JEE Main score and the availability of seats in your preferred branch. You can check the previous year cutoffs and the admission process on the NSIT websi
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2 years agoContributor-Level 8
A candidate can check NSIT cutoff 2023 on the official website of [JAC Delhi], which conducts the counselling and seat allotment process for admission to NSIT and other participating institutes. The cutoff is the minimum rank required to be eligible for admission in a particular branch and category. The cutoff depends on various factors such as the number of applicants, the difficulty level of JEE Main, the availability of seats, etc. The cutoff for NSIT 2023 has not been released yet.
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2 years agoContributor-Level 8
There are two NSIT colleges in India: one in Delhi and one in Patna. The seat intake for B.Tech at NSIT depends on the college and the specialisation you are interested in.
NSIT Delhi offers a full-time B.Tech course in 10 specializations with a total of 1692 seats. NSIT Patna offers a full-time B.Tech course in 5 specializations with an intake of 180 students each.
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2 years agoContributor-Level 8
The NSIT UG application form 2024 will be available from the second week of June 2024. The application form can be filled online through the official website of JAC. The candidates have to register themselves and pay the counselling fee to participate in the admission process. The last date to submit the application form and fee will be in the first week of July 2024. The admission will be based on the rank of JEE Mains and the preferences of the candidates. I hope this information helps you.
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2 years agoContributor-Level 8
No, you cannot join NSIT directly. You have to qualify for JEE Mains and apply for admission through JAC Delhi counselling. You also have to meet the eligibility criteria of having at least 60% aggregate marks in Physics, Chemistry, and Mathematics in 12th standard and passing English as a core or elective subject. I hope this clarifies your doubt.
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2 years agoContributor-Level 8
Yes, NSIT accepts JEE score for admission to its B.Tech programmes. According to some web search results, candidates should have at least 60% aggregate marks in Physics, Chemistry, and Mathematics in Qualifying exams / 12th from the recognised Center or State Board. In addition, they should also have passed English as a core or elective subject in 10+2. Also, the candidates have to pass in each subject separately. The admission process is based on the rank of JEE Mains followed by counselling and interview. I hope this answers your question.
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2 years agoContributor-Level 8
The fees structures for M.Tech programmes at VJTI Mumbai vary depending on the specialisations, the M.Tech course fee (2 Years) is 15,000 INR (Yearly) and goes up to 83,734 INR (Yearly) depending on the specialisation. The fee includes tuition fee, development fee, exam fee, and other charges. You can find the detailed fee structure for each specialisation on the official website of VJTI Mumbai. I hope this helps you.
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2 years agoContributor-Level 8
I can help you compare the M.Tech programmes at VJTI Mumbai and Institute of Chemical Technology, Mumbai based on some web search results. Here are some points to consider:
- Both institutes are highly reputed and ranked among the top engineering colleges in India by various sources.
- The admission process for both institutes is based on the rank of JEE Mains followed by counselling and interview. The total course fee for M.Tech at VJTI Mumbai is 3.24 lakhs, while at ICT Mumbai it ranges from 1.8 Lacs to 16 Lacs depending on the specialisation.
- ICT Mumbai offers 12 specialisations for M.Tech, while VJTI Mumbai offers only one ful
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2 years agoContributor-Level 8
The total intake in VJTI Mumbai of first year B.Tech students for the academic year 2023-2024 is 540. This includes 54 seats reserved for CIWGC, OCI, PIO, FN, and NRI candidates. The admission to B.Tech programmes is done through the JEE Main or MHT CET exams.
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2 years agoContributor-Level 8
The latest cutoff information for M.Tech at VJTI Mumbai is based on the entrance exams such as MHT CET and GATE. According to the web search results, the last round closing score for M.Tech course ranged between 8 and 357 for the General category students. The overall cutoff for MHT CET 2023 was 94.58 - 99.35 percentile for the General category students. You can check the detailed cutoff for different branches and categories on the official website of VJTI Mumbai or the State CET Cell, Maharashtra. I hope this information helps you.
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2 years ago
Contributor-Level 10
BTech is one of the most popular courses of VJTI Mumbai. When it comes to the placements, the VJTI Mumbai offers good placements annually. As per the latest report, the highest and average package offered during VJTI BTech CSE placement 2024 stood at INR 57 LPA and INR 20 LPA. The key highlights of VJTI BTech placements for the Class of 2024 are tabulated below:
Particulars | Placement Statistics (2024) |
|---|---|
the highest package | INR 57 LPA |
Average package | INR 20 LPA (Computer) INR 18 LPA (IT) INR 15 LPA (EnTc) |
Total eligible students | 88 (Computer) 86 (IT) 75 (EnTc) |
Total students placed | 72 (Computer) 71 (IT) 47 (EnTc) |
Placement percentage | 82% (Computer) 83% (IT) 63% (EnTc) |
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2 years agoContributor-Level 8
VJTI Mumbai accepts the scores of GATE and MAH-CET entrance exams for admission to M.Tech courses. The candidates must have a valid score in either of these exams and a BE/ B.Tech degree from any AICTE-recognized college or university with more than 50% marks. The selection process is purely merit-based and followed by counseling by CAP. You can find more information about the eligibility criteria, cutoffs, and syllabus on the websites of [VJTI Mumbai]. I hope this answers your question.
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