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This is a multiple choice answer as classified in NCERT Exemplar

Because it is a tertiary alkyl halide, the described reaction is a nucleophilic substitution that follows the S_N¹ mechanism. It's a two-step process. The first step is the gradual breaking of a polarised C-Br bond, which results in the formation of a carbocation and a bromide ion. To complete the substitution, the stable intermediate carbocation is attacked by the nucleophile OH⁻. (i) and (iv) are the right statements.

Correct Answer: option (A) and (iv)

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This is a multiple choice answer as classified in NCERT Exemplar

Because the carbon atom is transiently linked to five atoms, the intermediate (iii) is less stable than reactant (ii), which is coupled to four groups.

This is a multiple choice answer as classified in NCERT Exemplar

An S_N² reaction, also known as a nucleophilic substitution, is the reaction in question. The entering nucleophile causes the groups surrounding the carbon atom to migrate in the opposite direction of the nucleophile, causing the configuration of alkyl halides to invert. As a result, (b) and (d) will be in the opposite order. This reaction is also S_N² since there is just one phase in which OH^- is added and Cl^-  is removed at the same time. (i) and (ii) are the right answers.

Correct Answer: Option (A) and (B)

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This is a multiple choice answer as classified in NCERT Exemplar

An S_N² nucleophilic substitution reaction occurs when CH³Cl interacts with the hydroxide ion to produce CH³OH. Both OH -  and Cl - are nucleophiles with an excess of electrons in this reaction. Because the binding of OH -  and the leaving of Cl - occurs simultaneously in the transition state (c), the carbon atom is linked to just three hydrogens. As a result, the carbon atom becomes sp² hybridised.  Aand (C) are the right statements.

Correct Answer: Option (A) and (C)

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This is a multiple choice answer as classified in NCERT Exemplar

The Correct Answer is Option (iv).

If the halogen atom in all of the supplied alkyl halides is the same kind, the boiling point of a compound rises as the number of alkyl groups added increases. As the quantity and size of molecules and electrons grow, so do their attractions. As a result, the greater the boiling point, the larger the molecular weight of the alkyl halide. The boiling points of the following compounds are listed in ascending order: 1-Bromoethane 1-Bromopropane 1-Bromobutane Bromobenzene The right answer is (iv).

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This is a multiple choice answer as classified in NCERT Exemplar

The Correct Answer is Option (i).

The intermolecular force of attraction will grow as the surface area increases. As a result, the boiling point rises as well. The boiling point of a comparable alkyl halide rises with increasing molecular mass. Iodine has the greatest atomic mass. As a result, 1-iodobutane has the greatest boiling point.

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This is a multiple choice answer as classified in NCERT Exemplar

The Correct Answer is Option (iii).

The presence of electron releasing groups increases the reactivity of aryl halides; the fewer the electron releasing groups, the slower the rate of nucleophilic substitution. As a result, an increase in methyl groups decreases reactivity. The sequence of reactivity is (a) > (b) >   (c). The right answer is (iii).

This is a multiple choice answer as classified in NCERT Exemplar

The Correct Answer is option (iv).

( - NO₂) is an electron-withdrawing group that induces nucleophilic substitution when it is in the ortho and para positions. When this identical electron-drawing group is in the meta position, its impact is much reduced. The reactivity of aryl halides rises as the number of electron-withdrawing groups increases. As a result, the greater the number of electron-drawing groups, the greater the rate of nucleophilic substitution.

This is a multiple choice answer as classified in NCERT Exemplar

The Correct Answer is Option (iv).

Because the -CH₃  group is an electron releasing group, it reduces the reactivity of aryl halides in the ortho and para locations. As a result, aryl halides without electron releasing groups are more reactive. As a result, the order of reactivity is (a) > (c) > (d) (b). The right answer is (iv).