1.22 g of an organic acid is separately dissolved in 100 g of benzene (K_b = 2.6 K kg mol^-1) and 100 g of acetone (K_b = 1.7 K kg mol^-1). The acid is known to dimerize in benzene but remain as a monomer in acetone. The boiling point of the solution in acetone increases by 0.17°C. The increase in boiling point of solution in benzene in °C is x × 0^-2. The value of x is ________. (Nearest integer)

[Atomic mass : C = 12.0, H = 1.0, O = 16.0]

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Vishal Baghel | Contributor-Level 10

2 months ago

$Δ T_{b} = i K_{b} m$ $_{}_{}$

$m = \frac{w \times 1000}{M \times W_{s o l v e n t}}$

For acetone solution,

$0.17 = 1 \times 1.7 \times \frac{1.22 \times 1000}{M \times 100}$

For Benzene solution,

$2 A c i d \to {(A c i d)}_{2} ∴ i = 1 / 2$

$Δ T_{b} = i \times K_{b} \times m$

$= \frac{1}{2} \times 2.6 \times \frac{1.22 \times 1000}{122 \times 100} ° C$

= $0.13 ° C = 13 \times 1 0^{- 2} ° C$ $^{}$

$∴ x \times 1 0^{- 2} = 13 \times 1 0^{- 2}$

$∴ x = 13$

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