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Simple Pendulum Physics Oscillations Physics Class 11th

T₀ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its initial value, the modified time period is:

Option 1 -

T₀

Option 2 -

8 π T₀

Option 3 -

4 T₀

Option 4 -

$\frac{1}{4} T_{0}$

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 4

Detailed Solution:

$\frac{T}{T'} = \frac{2 π \sqrt[]{\frac{l}{g}}}{2 π \sqrt[]{\frac{l}{\frac{16}{g}}}}$

$\Rightarrow \frac{T}{T'} = \frac{1}{(\frac{1}{4})} = 4$

$\Rightarrow T' = \frac{T}{4}$

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T₀ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its initial value, the modified time period is:

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T₀ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its initial value, the modified time period is: