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2011-04-30 16:57:39
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Satish Patra
Contributor-Level 6
contact mee soon in my mail id satishpatra2007@gmail.com soon 2 get the details
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2011-04-30 16:56:10are admission form of NIT KUK for admission in Mtech 2011 out...???if yes do provide me the link....
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2011-04-30 16:52:46
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2011-04-30 16:49:15
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2011-04-30 16:48:28
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2011-04-30 16:46:14
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ASBM Team
Beginner-Level 5
Dear Alok,
This is really nice to know that you are interested to know more about ASBM.CONSISTENTLY EXCELLENT PLACEMENT RECORD SINCE INCEPTION. ASBM Bhubaneswar 256 offers from 55 companies for 249 students.The average package is around 4.6lacs/annum.You can find the details in our website www.asbm.ac.in.
This is really nice to know that you are interested to know more about ASBM.CONSISTENTLY EXCELLENT PLACEMENT RECORD SINCE INCEPTION. ASBM Bhubaneswar 256 offers from 55 companies for 249 students.The average package is around 4.6lacs/annum.You can find the details in our website www.asbm.ac.in.
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2011-04-30 16:44:58
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2011-04-30 16:43:34
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Becky Zhang
Beginner-Level 1
Absolutely, I would recommend you to do your PG in China itself. BTW from which university have you done your MBBS ?
I am in Qingdao and would to love to hear your thoughts.
I am in Qingdao and would to love to hear your thoughts.
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2011-04-30 16:43:33
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KR MANGALAM INSTITUTE
Beginner-Level 5
Hi Ritesh,
If you want take good job opportunity then do MBA regular.
If you want take good job opportunity then do MBA regular.
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2011-04-30 16:34:28
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Yunus Ahmed
Beginner-Level 3
We were nominated as the fatsest growing institution last year. You can check on the website you will find a video of the director representing the institution on CNBCTV18
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2011-04-30 16:34:11
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2011-04-30 16:32:45
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2011-04-30 16:31:16
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Manish Ramachandran
Contributor-Level 10
Hi Pranav.
secx(tanx + cosx) first simplify by distributing the secx
secx(tanx + cosx) = secxtanx + secxcosx= secxtanx + 1 now, differentiate using theproduct rule on secxtanx
d (secxtanx + 1)= [secxsecx + tanxsecxtanx] + 0dx= secx[secx + tanx] ANSWER
= secx[secx + (secx 1)]
= secx[2secx 1)] alternate ANSWER
All the best.
Regards.
Manish
secx(tanx + cosx) first simplify by distributing the secx
secx(tanx + cosx) = secxtanx + secxcosx= secxtanx + 1 now, differentiate using theproduct rule on secxtanx
d (secxtanx + 1)= [secxsecx + tanxsecxtanx] + 0dx= secx[secx + tanx] ANSWER
= secx[secx + (secx 1)]
= secx[2secx 1)] alternate ANSWER
All the best.
Regards.
Manish
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2011-04-30 16:31:05
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2011-04-30 16:28:18
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2011-04-30 16:27:32
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2011-04-30 16:27:11
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